3x^2-12x+9.5=0

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Solution for 3x^2-12x+9.5=0 equation:



3x^2-12x+9.5=0
a = 3; b = -12; c = +9.5;
Δ = b2-4ac
Δ = -122-4·3·9.5
Δ = 30
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{30}}{2*3}=\frac{12-\sqrt{30}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{30}}{2*3}=\frac{12+\sqrt{30}}{6} $

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